In this problem you will predict the pH of a buffer solution and then predict the new pH after you add NaOH or HCl. Write your answers to three decimal places (X.XXX). The Ka of HC2H3O2 is 1.8×10−51.8×10−5.
1) Calculate the pH of a buffer made from mixing 11.011.0 mL of 0.080.08 M NaC2H3O2 and 9.29.2 mL of 0.080.08 M HC2H3O2.
2) Calculate the pH of the buffer when 5.25.2 mL of 0.0090.009 M NaOH is added to the buffer prepared in part 1.
3) Calculate the pH of the buffer when 4.24.2 mL of 0.0080.008 M
HCl is added to the buffer prepared in part 1.
1)
mmoles of NaC2H3O2 = 11 x 0.080 = 0.88
mmoles of HC2H3O2 = 9.2 x 0.080 = 0.736
pH = pKa + log [salt / acid]
= 4.74 + log [0.88 / 0.736]
pH = 4.823
2)
mmoles of NaOH = 5.2 x 0.0090 = 0.0468
pH = pKa + log [salt + C / acid - C]
= 4.745 + log [0.88 + 0.0468 / 0.736 - 0.0468]
pH = 4.874
3)
mmoles of HCl = 4.2 x 0.008 = 0.0336
pH = 4.745 + log [0.88 - 0.0336 / 0.736 + 0.0336]
pH = 4.786
In this problem you will predict the pH of a buffer solution and then predict the...
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