Let q1=−2.0× 10−6C, q3=5× 10−6C. The distance between q1 and q3 is r=1.0 m, and b=0.25...
Let q1=−2.0× 10−6C, q3=5× 10−6C. The distance between q1 and q3 is r=1.0 m, and b=0.25 m. How much work in Joules is done by the electric field if q2=1.0× 10−6C is moved from its current position (distance b from q1) to the black dot (distance b from q3)?
Homework Answers
Work done = Change in PE
Initially
k(-2*5*10^-12/1+ -2*1*10^-12/0.25 + 1*5*10^-12/0.75)
=9*10^9(-2*5*10^-12/1+ -2*1*10^-12/0.25 + 1*5*10^-12/0.75)
= 0.066 J
Change = 0.168 J
= -0.102 J
Finally
k(-2*5*10^-12/1+ -2*1*10^-12/0.75 + 1*5*10^-12/0.25)
= 9*10^9(-2*5*10^-12/1+ -2*1*10^-12/0.75 + 1*5*10^-12/0.25)
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