We have, Voltage, V = 9 V
Current, I = 0.1 amp
Time, t = 1 hr = 60 min = 3600 sec
Power, P = V x I = 9 x 0.1 = 0.9 W or 0.9 J/s
Energy Generated = Power x Time = 0.9 x 3600 = 3240 J = 3.24 kJ
Energy remaining = Energy generated - Energy Lost = 3.24 - 2 = 1.24 kJ
The energy remaining is 1.24 kJ
The energy in the battery is stored as chemical energy. This is converted into electrical energy and supplied to the camp light by conduction. The camp light turns this electrical energy into light and heat energy. The light energy is the desirable part while the heat is wasted into the environment. The heat energy is transferred/dissipated to the environment by radiation.
Hope it helps.
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