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Calculate the % empty space in 100 mL of air. r Yo
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Answer #1

You know 6.02 x 10^23 molecules/mole will occupy 22.4 L. Therefore, 100 mL should contain:

6.02 x 10^23 molecules/mole x 1 mol / 22.4L x 0.1 L = 2.68 x 10^21 molecules

Each molecule occupies a volume of 3.8 x 10^-24 cm3/molecules so multiply the number times the volume to obtain the total volume occupied.

(V = 2.68 x 10^21 molecules x 3.8 x 10^-24 cm3/molecules = 0.010 L). I get 0.010 L rounded to two significant figures.

So the percent of occupied space is (0.01/0.1) * 100 = 10% so the empty space must be 100%-10% = 90%. Or you could have said 0.1 = original space - 0.01 occupied = 0.09 L empty which is (0.09/0.1)*100 = 90%. heck my work. Check for typos.

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