Homework Answers
Here, A is the limiting reagent, as it will get consumed completely and B will still be remaining. Therefore, A will be 0 at equilibrium. Now, we should find how much B has reacted.
3A + 2B = 4C
A + 2/3 B = 4/3 C
1.2A + 0.8B = 1.6C
Thus, 0.8 moles of B has reacted, and 3.7-0.8 = 2.9 moles of B remained at equilibrium.
[A] = 0 M
[B] = 2.9 M
[C] = 1.6 M
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= 3.13 x 1027
3A(g) + 2B(g)
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placed in a 1.00 L container, what are the concentrations of A, B,
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