If you invest $1,200 each year for the next 12 years at a rate of 4.25%, compounded monthly, what will be the future value of this investment?
We use the formula:
A=P(1+r/1200)^12n
where
A=future value
P=present value
r=rate of interest
n=time period.
Hence
A=$1200(1+0.0425/12)^(12*11)+$1200(1+0.0425/12)^(12*10)+$1200(1+0.0425/12)^(12*9)+.............+$1200(1+0.0425/12)^(12*1)+$1200
=$1200[(1+0.0425/12)^(12*11)+(1+0.0425/12)^(12*10)+(1+0.0425/12)^(12*9)+.............+(1+0.0425/12)^12+1]
=$1200*15.31671492
which is equal to
=$18380.06(Approx).
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