n a group of college students, the ratio of men to women is 3:2 (i.e., 3 to 2). In a recent survey, 65% of the men in this group selected hiking as their favorite outdoor activity whereas 40% of the women in the group selected hiking as their favorite outdoor activity. An individual is randomly selected from this group. What is the probability that hiking is not his/her favorite outdoor activity? Round your result to 2 significant places after the decimal (For example, 0.86732 should be entered as 0.87).
Given,
P(Men) = 3/(3 + 2) = 3/5
P(Women) = 2/(3 + 2) = 2/5
P(Hikin |Men) = 0.65
P(Hiking| Women) = 0.40
So,
P(Hiking is not his/her favorite outdoor activity)
= P(Men)*P(Not hiking | Men) + P(Women)*P(Not hiking | Women)
= (3/5)*(1 - 0.65) + (2/5)*(1 - 0.40)
= 0.45
n a group of college students, the ratio of men to women is 3:2 (i.e., 3...
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2. A committee of 3 is to be selected from a group of 4 men and
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probability that the committee consists of at least one women?
use this formula to solve.
We'll often need count the number of ways of sampling k of n items. You may recall this as "n choose k" denoted as n! k!(n - k)! k/
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