I got all wrong please answer quick
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I got all wrong please answer quick
Determine the rate constant from the concentration-time dependence. Calculate...
The half-life of a reaction, t1/2, is the time it takes for the reactant concentration [A]...
The half-life of a reaction,
t1/2, is the time it takes for the reactant concentration [A] to
decrease by half. For example, after one half-life the
concentration falls from the initial concentration [A]0 to [A]0/2,
after a second half-life to [A]0/4, after a third half-life to
[A]0/8, and so on. on. For a first-order reaction, the half-life is
constant. It depends only on the rate constant k and not on the
reactant concentration. It is expressed as t1/2=0.693k For a...
For this question, I got the answer as 0.00001172. It was marked wrong, I dont know...
For this question, I got the answer as 0.00001172. It was
marked wrong, I dont know what I did wrong. the second picture are
my calculations.
uestion 8 O out of 3 points Hydrogen peroxide decomposes into water and oxygen in a first-order process. H 20 2(aq) + H200) liq+ 1/2O2(e) At 20.0°C, the half-life for the reaction is 3.92 x 10 seconds. If the initial concentration of hydrogen peroxide is 0.52 M, what is the concentration after 7.00 days?...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt[A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute [A]02[A]02 for [A][A] and rearrange the equation to: t1/2=0.693k t1/2=0.693k This equation calculates the...
The integrated rate law allow chemists to predict the reactant concentration after a certain amount of...
The integrated rate law allow chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A] = [A]oe -Rt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute Z" for [A] and rearrange the equation to: A) 1/2= 0093...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of...
The integrated rate law allows
chemists to predict the reactant concentration after a certain
amount of time, or the time it would take for a certain
concentration to be reached. The integrated rate law for a
first-order reaction is: [A]=[A]0e−kt Now say we are particularly
interested in the time it would take for the concentration to
become one-half of its initial value. Then we could substitute
[A]02 for [A] and rearrange the equation to: t1/2=0.693k This
equation calculates the time...
For a first-order reaction, the half-life is constant. It depends only on the rate constant k...
For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t1/2=0.693kt1/2=0.693k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t1/2=1k[A]0 Part A. A certain first-order reaction (A→products) has a rate constant of 3.00×10−3 s−1 at 45 ∘C∘C. How many minutes does it take for the concentration of the reactant, [A],...
1. A certain first order reaction has a rate constant of 0.036 min-1. How much of the reactant will remain if the reacti...
1. A certain first order reaction has a rate constant of 0.036 min-1. How much of the reactant will remain if the reaction is run for 2.5 hours and the initial concentration of the reactant is 0.31 M? 2. A certain first order reaction has a rate constant of 0.036 min-1. How much of the reactant will remain if the reaction is run for 2.5 hours and the initial concentration of the reactant is 0.31 M? 3. The rate constant...
For a first-order reaction, the half-life is constant. It depends only on the rate constant k...
For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t 1/2 = 0.693 k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t 1/2 = 1 k[A ] 0 Part A A certain first-order reaction ( A→products ) has a rate constant of 9.90×10−3 s −1 at 45 ∘...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute [A]02 for [A] and rearrange the equation to: t1/2=0.693k This equation calculates the time...
A certain first-order reaction (A products) has a rate constant of 5.40 10-3 s I at...
A certain first-order reaction (A products) has a rate constant of 5.40 10-3 s I at 45 °C How many minutes does it take for the concentration of the reactant, [A], to drop to 6.25% of the original concentration? at 27 °C A certain second-order reaction (B-products) has a rate constant of 1.05x10-3 M 1.s and an initial half-life of 266 s What is the concentration of the reactant B after one half-life?
The half-life of a reaction,
t1/2, is the time it takes for the reactant concentration [A] to
decrease by half. For example, after one half-life the
concentration falls from the initial concentration [A]0 to [A]0/2,
after a second half-life to [A]0/4, after a third half-life to
[A]0/8, and so on. on. For a first-order reaction, the half-life is
constant. It depends only on the rate constant k and not on the
reactant concentration. It is expressed as t1/2=0.693k For a...
For this question, I got the answer as 0.00001172. It was
marked wrong, I dont know what I did wrong. the second picture are
my calculations.
uestion 8 O out of 3 points Hydrogen peroxide decomposes into water and oxygen in a first-order process. H 20 2(aq) + H200) liq+ 1/2O2(e) At 20.0°C, the half-life for the reaction is 3.92 x 10 seconds. If the initial concentration of hydrogen peroxide is 0.52 M, what is the concentration after 7.00 days?...
The integrated rate law allow chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A] = [A]oe -Rt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute Z" for [A] and rearrange the equation to: A) 1/2= 0093...
The integrated rate law allows
chemists to predict the reactant concentration after a certain
amount of time, or the time it would take for a certain
concentration to be reached. The integrated rate law for a
first-order reaction is: [A]=[A]0e−kt Now say we are particularly
interested in the time it would take for the concentration to
become one-half of its initial value. Then we could substitute
[A]02 for [A] and rearrange the equation to: t1/2=0.693k This
equation calculates the time...
A certain first-order reaction (A products) has a rate constant of 5.40 10-3 s I at 45 °C How many minutes does it take for the concentration of the reactant, [A], to drop to 6.25% of the original concentration? at 27 °C A certain second-order reaction (B-products) has a rate constant of 1.05x10-3 M 1.s and an initial half-life of 266 s What is the concentration of the reactant B after one half-life?
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