Answer:
Given,
xbar = 10
Standard deviation = 2
Sample n = 30
degree of freedom = n - 1
= 30 - 1
= 29
alpha = 0.05
t(alpha/2 , df) = t(0.05/2 , 29)
= +/- 2.04523
Critical t value = 2.045
test statistic = (x - u)/(s/sqrt(n))
substitute values
= (10 - 0)/(2/sqrt(30))
test statistic = 27.39
Critical t value = 2.045
Given the following data, assess the 95% confidence interval. Use Table B to find the t-score....
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95%
confidence interval (PART A and B)
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95%
z-interval or t-interval
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