Please read the question carefully and in full and then answer it (using C language and any necessary libraries).
(I am not sure what the expert's mean by when to move to using pipe. I guess if you need to, then you can use a random time or any exact time but make sure to put a comment next to it).

you might use the below code to give you some idea:
#include<stdio.h>
#include<stdlib.h>
#include<unistd.h>
#include<sys/types.h>
#include<string.h>
#include<sys/wait.h>
void main()
{
int fd1[2];
int fd2[2];
int pid1 = 0, pid2 = 0;
/* register pipe 1 */
if(pipe(fd1) == -1)
{
perror("Pipe1");
return;
}
/* register pipe 2 */
if(pipe(fd2) == -1)
{
perror("Pipe2");
return;
}
/* create child 1 process */
if((pid1 = fork()) == 0)
{
int i=0;
char data[64] = {0};
/* send data in pipe 1 from 1 to
100 */
for(i=1; i<=100; i++)
{
memset(data, 0 ,
sizeof(data)); // clear buffer
sprintf(data,"child - 1, data - %d\n",i); // copy data in child 1
into data
write(fd1[1],data,strlen(data)); // send data over pipe
sleep(0.01);
}
memset(data, 0 , sizeof(data)); //
clear buffer
sprintf(data,"end");
write(fd1[1],data,strlen(data)); //
send end to pipe to indicate data is over
close(fd1[1]);
}
else
{
/* create child 2 process */
if((pid2 = fork()) == 0)
{
int i=0;
char data[64] =
{0};
/* send data in
pipe 1 from 1 to 100 */
for(i=1;
i<=100; i++)
{
memset(data, 0 , sizeof(data)); // clear
buffer
sprintf(data,"child - 2, data - %d\n",i); //
copy data and child 2 in data
write(fd2[1],data,strlen(data)); // send data in
pipe
sleep(0.01);
}
memset(data, 0 ,
sizeof(data)); // clear buffer
sprintf(data,"end");
write(fd2[1],data,strlen(data)); // send end to pipe to indicate
data is over
close(fd2[1]);
}
else
{
char data1[64] =
{0};
char data2[64] =
{0};
int status =
0;
int flag1 =
0;
int flag2 =
0;
close(fd1[1]);
// close fd1 writing end
close(fd2[1]);
// close fd1 writing end
while(1)
{
memset(data1, 0 ,sizeof(data1)); // clean
buffer
memset(data2, 0 ,sizeof(data2));
if(flag1 != 1 )
read(fd1[0], data1,
sizeof(data1)); // read from pipe 1
if(flag2 != 1)
read(fd2[0], data2,
sizeof(data2)); // read from pipe 2
if(strstr(data1,"end")) // if got end close
pipe
{
printf("end 1\n");
if(flag2 == 1) // if child 2
process over
break; //
break the loop
flag1 =1;
close(fd1[0]); // close fd1
reading end
}
else if(strstr(data2, "end"))
{
printf("end 2\n");
if(flag1 == 1) // if child 1
process over
break; //
break the while loop
flag2 = 1;
close(fd2[0]); // close fd2
reading end
}
if(strstr(data1,"child") &&
strstr(data2,"child"))
{
if(flag1 != 1)
printf("%s\n",data1);
if(flag2 != 1)
printf("%s\n",data2);
}
}
waitpid(-1,
&status, 0); // wait for child to complite
waitpid(-1,
&status, 0); // wait for child to complite
}
}
}
Fork-It is used to create new process duplicating the calling process
USING WAIT PID
#include <stdio.h>
#include<stdlib.h>
#include<unistd.h>
#include <sys/wait.h>
void child process (void); /child process/
void parent process(void); /parent process/
void main(void)
{
pid_t pid;
pid =fork();
if(Pid==0)
child process();
else
parent process();
}
void Childprocess(void)
{
int i;
for(i=1;i<=max count;i ++)
printf("from child,value=%d\n");
printf("child process done\n");
}
void parentprocess(void)
{
int i;
for(i=1;i<=max count;i ++)
printf("from child value=%d\n");
printf("child process done\n");
}
//using waitpid()
for(i=1:i<=max:i ++)
{
pid_t cpid = waitpid(pid[i] &stat, 0);
if(i=o,(stat))
printf("child %d with status%d\n, cpid(stat") )
return 0;
}
Please read the question carefully and in full and then answer it (using C language and...
C LANGUAGE PROGRAM: You have the program that creates a parent and child. They communicate via the pipe. The parent writes into the pipe and child reads the data from the pipe. All you got to is replace FILL_IN_THE_BLANK with appropriate values or function names and just type the values of each TASKS, I don't need the c program. TASK_1 = TASK_2 = TASK_3 = TASK_4 = 4 of them [ 5 points each ] -------------------------------------------------------------------------------------------- When you run the...
/* myloggerd.c * Source file for thread-lab * Creates a server to log messages sent from various connections * in real time. * * Student: */ #include <stdio.h> #include <sys/types.h> #include <sys/stat.h> #include <unistd.h> #include <fcntl.h> #include <sys/socket.h> #include <sys/un.h> #include <stdlib.h> #include <pthread.h> #include "message-lib.h" // forward declarations int usage( char name[] ); // a function to be executed by each thread void * recv_log_msgs( void * arg ); // globals int log_fd; // opened by main() but accessible...
Rewrite the program as a set of two programs that utilize a named pipe “ages” in the current folder for IPC and implement the same function as discussed above. #include <stdio.h> #include <unistd.h> #include <stdlib.h> #include <sys/types.h> int main(void) { int fd[2], nbytes; pid_t childpid; int users = 95; char mystring[80]; char readbuffer[80]; char digit1,digit2; digit1 = (char) users%10; digit2 = (char ) users/10; mystring[0] = digit1; mystring[1] = digit2;...
Modify the client server system program given below so that instead of sendto() and recvfrom(), you use connect() and un-addresssed write() and read() calls. //Server.c #include #include #include #include #include #include #include #include #include #include # define PortNo 4567 # define BUFFER 1024 int main(int argc, char ** argv) { int ssd; int n; socklen_t len; char msg[BUFFER]; char clientmsg[BUFFER]; struct sockaddr_in server; struct sockaddr_in client; int max_iterations = 0; int count = 0, totalChar = 0, i = 0;...
Modify the template program below and include the following additional functionalities: - Instead of 3 children processes, create 6 children processes. - 6 children processes are connected to the parent process via 6 pipes, one for each pair, child1-parent, child2-parent, child3-parent, .... - Child keeps writing to the pipe with 1 second apart between consecutive writes (as in child() in p. 167). - Keyboard inputs need to be monitored as in the original code. - Parent keeps reading from the...
Write code that forks into two processes: a parent process, and a child process. Your code will be called with command-line arguments consisting of negative integers. Do not worry about bad command-line arguments such as "xyz". Your code will not be tested in this way. The parent process will take the arguments to main(), convert them into ints by calling atoi(), and send those ints one at a time to the child process through a pipe (one call to write()...
Directions: use only the signal mechanism system calls don’t use ( wait() or pipe() )in this problem. You can still read/write from/to a file. You must use ( kill() and pause() ) system calls. rewrite code below to do kill and pause system calls #include <fcntl.h> #include <unistd.h> #include <stdio.h> #include <stdlib.h> #include <string.h> #include <sys/wait.h> // Function ptototypes int readX(); void writeX(int); int main() { int pid; // pid: used to keep track of the child process int x...
This is for a Unix class.
Please fully answer the question :)
The figure that it references is on the attached picture.
I have also added the information that comes with that
figure.
3.3 Assume that a process executes the following three function calls: fdl-open (path, oflags); fd2 = dup ( fd ) ; fd3-open (path, oflags); Draw the resulting picture, similar to Figure 3.9. Which descriptors are affected by an fentl on fdl with a command of F_SETFD? Which...
GIVEN CODE- FILL IN THE
BLANK!
#include <fcntl.h>
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/wait.h>
// Function ptototypes
int readX();
void writeX(int);
int main() /// chi read x ---> divi ---> write x into file
---> par read x --> sub--> write x into file---> chi
read x-->etc
{
int pid;
// pid: used to keep track of the child
process
int x = 19530; // x:
our value as integer
...
Please help in C: with the following code, i am getting a random 127 printed in front of my reverse display of the array. The file i am pulling (data.txt) is: 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 when the reverse prints, it prints: 127 9 8 7 6 5 4 3 2 1 0 9 8 7 6 5 4 3 2 1 not sure why...please...