Homework Answers
Solution :
degrees of freedom = n - 1 = 39 - 1 = 38
t
/2,df
= t0.025,38 = 2.024
Margin of error = E = t
/2,df
* (s /
n)
= 2.024 * (7 /
39)
Margin of error = E = 2.27
The 95% confidence interval estimate of the population mean is,
±
E
= 59 ± 2.27
= ( 56.73, 61.27 )
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