Do a power analysis to determine the statistical power at the p=0.05 and p=0.01 levels. For...
Do a power analysis to determine the statistical power at the p=0.05 and p=0.01 levels. For the power analysis, seek power for a difference in means of 2.79.
[11.540 8.203 8.214 13.165 11.451 13.015 11.060 10.488 8.849 8.271]
[4.708 8.013 9.886 7.026 6.051 5.546 7.914 9.951 9.880 7.381]
Homework Answers
ANSWER:
Given that,
| Group 1 | Group 2 | |
| 11.540 | 4.708 | |
| 8.203 | 8.013 | |
| 8.214 | 9.886 | |
| 13.165 | 7.026 | |
| 11.451 | 6.051 | |
| 13.015 | 5.546 | |
| 11.060 | 7.914 | |
| 10.488 | 9.951 | |
| 8.849 | 9.880 | |
| 8.271 | 7.381 | |
| Sum = | 104.256 | 76.356 |
| Average = | 10.426 | 7.636 |
| \sum_i X_{ij}^2 =∑iXij2= | 1120.799442 | 614.59118 |
| St. Dev. = | 1.94 | 1.873 |
| SS = | 33.8680884 | 31.5673064 |
| n = | 10 | 10 |
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