How many times more basic is sodium hydroxide (pH 14.0) than ammonia (pH 11.0)?
Solution :-
Using the given ph values lets calculate the concentration of the [OH-] for both
pOH= -log[OH-]
[OH-] = antilog [-pOH]
pOH for the NaOH = 0
therefore the concnetration of the NaOH that is OH^- = 1.0 M
and [OH-] from NH3 is calculated as
pOH = 14 - 11 = 3
[OH-] = antilog [-3]
[OH-] = 0.001 M
now lets calculate the ratio
NaOH / NH3 = 1.0 / 0.001 = 1000
Therefore NaOH is 1000 times greater base than NH3
How many times more basic is sodium hydroxide (pH 14.0) than ammonia (pH 11.0)?
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