Perform each of the following calculations and express the answer with the correct number of significant...

Question

Question

science chemistry

Answer 1

Answer #1

a) =0.6274×1.00×10³/36.13 (36.13347612.... rounds upto 36.13 as 2.205 has 4 significant figures)

=0.02×10³ =2.0×10 (0.017365...... rounds upto 2 significant figures)

Note: Exact number has infinite number of significant figures

b) = 70×10^-15 (72 rounds upto one significant figure )

c) = 5.70×10^-23 ( 5.701268....... rounds upto 3 significant figures)

d) =35.8×10^-4 (35.83735.......rounds upto 3 significant figures)

Note: Multiplication and Division- consider the lowest number of significant figures

Answer 2

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