Question

Find z such that 73% of the standard normal curve lles to the right of z. (Round your answer to two decimal places.) Sketch the area described.

Answer 1

Answer 2

SOLUTION :

Let the value of z be a so that P(z > a) = 73% = 0.73

Value of a will be negative as it lies to the left of z = 0 and P(z > 0) = 50%.

So,

P(z < a) = 1 - 0.73 = 0.27

From cumulative ND table :

a = - 0.613 

Hence, z = - 0.613 to the right of which 73% standard normal curve lies. (ANSWER)

Graph :

2nd graph on the top row represents the given case. Where z = - 0.613 and area to the right of z is 73%.