Homework Answers
Answer
332.2nm
UV light
Energy of photon , E = hc/
where,
h = planck constant, 6.626×10-34J.s
c = speed of light, 2.998×108m/s
= wavelength of light
= hc/E
= 6.626 ×10-34J.s × 2.998 ×108m/s / 5.98×10-19J
= 3.322×10-7m
= 332.2 × 10-9 m
= 332.2 nm
Therefore,
UV light is suitable.
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