What speed should a satellite of mass 2500 kg at 7.5 x 10^9 kn above the center of the Sun, of mass 1.99 x 10 ^30 kg be traveling at in order to stay in orbit? (in m/s, G= 6.67x 10^-11 N (m/kg)^2)
a) 2.4 x 10 ^7 m/s
b) 1.6 x 10 ^2 m/s
c) 9.3 x 10^6 m/s
d) 8.3 x 10^ 4 m/s
e) 1.3 x 10^ 5 m/s
The answer I am getting is 4206.87 m/s
What speed should a satellite of mass 2500 kg at 7.5 x 10^9 kn above the...
Mele is no reaction in this case 14. A satellite of mass ms = 2500 kg and a spee sms – 2500 kg and a speed of 2200 m/s is placed on a circular orbit of radius raround Mars. Mars has a mass MMars = 6.39 x 1023 kg and a radius RMars = 3.40 X 1 = 6.39 x 1023 kg and a radius RMars = 3.40 x 106 m. The gravitational constant G = 6.67 x 10-11 Nm2/kg?....
A satellite with mass 898 kg is in a circular orbit with an orbital speed of 5840 m/s around the earth. a) What is the new orbital speed after friction from the earth's upper atmosphere has done −7.5×10^9 J of work on the satellite? Express your answer with the appropriate units. b) Does the speed increase or decrease?
A satellite with mass 748 kg is in a circular orbit with an orbital speed of 9040 m/s around the earth. What is the new orbital speed after friction from the earth's upper atmosphere has done -7.5×109 J of work on the satellite? Express your answer with the appropriate units.
Satellite A has mass MA 1997 kg and moves in a circular orbit of radius RA - 10.3x10 m around a planet (measured from its center). The mass of the planet is M - 6x10 kg and the universal gravitational constant is G = 6.67 x 10-11 NmⓇ/kg. 1) What is the speed V of the satellite ? OV - 7605 m/s OV- 13152 m/s OV - 6233 m/s OV-5109 m/s OV-8976 m/s Submit 2) Satellite B moves in a...
101 Scientists want to place a 4400 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2670 m/s in a perfectly circular orbit. Here is some information that may help solve this problem: mmars = 6.4191 x 1023 kg 'mars = 3.397 x 106m G = 6.67428 x 10-11 N-m2/kg 1) What radius should the satellite move at in its orbit? (Measured frrom the center of Mars.) m Submit 2) What is...
Calculate the speed (in m/s) of a satellite in an orbit , h=1699 km above the Earth's surface. Radius of the Earth, R=6.38*106 m, Mass of the Earth, M=5.98*10 24 kg. (Hint: Find the distance of the satellite from the center of the earth, ie r=h+R, first, see figure below)
I need the answers for #3 and #5
Scientists want to place a 4400 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2670 m/s in a perfectly circular orbit. Here is some information that may help solve this problem: mmars = 6.4191 x 1023 kg 'mars = 3.397 x 106m G = 6.67428 x 10-11 N-m2/kg? 1) What radius should the satellite move at in its orbit? (Measured frrom the center...
A small asteroid (mass of 150 g ) strikes a glancing blow at a satellite in empty space. The satellite was initially at rest and the asteroid was traveling at 2500 m/s . The satellite's mass is 140 kg . The asteroid is deflected 10 ∘ from its original direction and its speed decreases to 1200 m/s , but neither object loses mass. a.Determine the direction and of the satellite after the collision. Assume the initial direction of the asteroid...
A satellite is in a circular orbit around the Earth at an altitude of 2.24 x 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 x 106 m, and the mass of the Earth is 5.98 x 1024 kg.) h (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite....
A satellite of Earth is moving in a circular orbit with Earth at its center, at a constant speed of 2.00 km/s. a.) How high is the satellite above the surface of the Earth? b.) How long does it take for the satellite to complete one revolution? Helpful info (but not all of it is relevant!): universal gravitational constant G is = 6.674 x 10^-11 m^3/kg s^2 (units may also be expressed as N m^2/kg^2) Mass of Sun = 1.989...