Question

a) (C language) Let’s consider an integer array of size 10. (10 marks, each part is 2 marks)
int a[10];
I. How would you assign a pointer, called pA, to store the address of element 0 of this array? Write
the C code for your answer.
II. Using pA, how would you obtain the value of the next element (element 1) of the array?
III. Explain in 2-3 sentences what the statement pA = a[1]; would do.
IV. Is the statement a = pA; valid (would it cause compilation errors)? How about a++;? Explain
briefly in 3-4 sentences.
V. Write a C code to print all the elements from this array.

Answer 1

Solution:

So, we have an array int a[10];

I. How would you assign a pointer, called pA, to store the address of element 0 of this array? Write
the C code for your answer.

=> int *pA= &a[0];

II. Using pA, how would you obtain the value of the next element (element 1) of the array?

=> pA++; //by just incrementing the pointer by one the pointer will start to point at the next element value of the array a.

*pA is the value of the element at 1 position in the array a.

III. Explain in 2-3 sentences what the statement pA = a[1]; would do.

=> The statement will store the element value in the variable pA, but if pA is a pointer variable then there will be an error at compile time saying cannot assign int to an address.

IV. Is the statement a = pA; valid (would it cause compilation errors)? How about a++;? Explain
briefly in 3-4 sentences.

=> Yes, the statement is valid.

because a is also a pointer pointing to the base element of array a which is a[0], and pA is also of pointer type.

a++ will assign the address of a[1] to the pointer variable a.

V. Write a C code to print all the elements from this array.

#include <stdio.h>

#include<conio.h>

int main()

{

int a[10]={0};

for(int i=0; i<10; i++)

{

printf("The element at %d index is= %d", i, a[i]); //printing the elements of the array

return 0;

}

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