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Using a pH meter, the pH of a lemon was found to be 2.24. Determine the [H+]. Titration of a 1.0 ml sample of the above juice to a pH of approximately 7 required 02.34 ml of 0.10M NaOH. Determine the total [H+] in the juice Explain why the above two numbers are not the same.
pH= -log(H+) …………………………………….1
Therefore from equation 1,
Or, log (H+) = -2.24
Or, [H+] = 10-2.24
[H+] = 0.00575
Now in the second case,
V1 = 1 ml V2 =2.34 ml (S= concentration of solution)
S1 =? (M) S2 =0.10 (M)
Now the required formulae,
V1S1 = V2S2
Or, 1 x S1 = 2.34 x 0.10 (putting all the values)
Or, S1 =0.234 (M)
Citric acid is present in lemon. Citric acid has 3 ionizable COOH groups. In presence of NaOH (strong base), it completely ionizes and produces 4 protons which react with NaOH and produces water.
C(OH)(COOH)3 = C(O-1)(COO)33- + 4 H+
Therefore, [H+] = 4 x 0.234
The two values are different is due to in presence of strong base (NaOH), OH protons also ionizes and produces protons.
Using a pH meter, the pH of a lemon was found to be 2.24. Determine the...
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