Question

import java.util.Scanner;

public class TempConvert {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);

//ask the user for a temperature
System.out.println("Enter a temperature:");
double temp = scnr.nextDouble();

//ask the user for the scale of the temperature
System.out.println("Is that Fahrenheit (F) or Celsius (C)?");
char choice = scnr.next().charAt(0);

if(choice == 'F') {
//convert to Celsius if given temperature was Fahrenheit
System.out.println(temp + " degrees Fahrenheit is " + ((5.0/9) * (temp-32)) + " degrees Celsius");
} else {
//convert to Fahrenheit if given temperature was Celsius
System.out.println(temp + " degrees Celsius is " + (((9*temp)/5) + 32) + " degrees Fahrenheit");
}
}
}

How do I fix this code to have the output be rounded rather than long decimals. Like 35.6 over 35.555555559 if that makes sense. I don't know how to fix it within the code. That's the only thing that's wrong.

Answer 1

import java.util.Scanner;

public class TempConvert {
    public static void main(String[] args) {
        Scanner scnr = new Scanner(System.in);

//ask the user for a temperature
        System.out.println("Enter a temperature:");
        double temp = scnr.nextDouble();

//ask the user for the scale of the temperature
        System.out.println("Is that Fahrenheit (F) or Celsius (C)?");
        char choice = scnr.next().charAt(0);

        if(choice == 'F') {
//convert to Celsius if given temperature was Fahrenheit
            System.out.println(temp + " degrees Fahrenheit is " + Math. round(((5.0/9) * (temp-32)) * 100.0) / 100.0 + " degrees Celsius");
        } else {
//convert to Fahrenheit if given temperature was Celsius
            System.out.println(temp + " degrees Celsius is " + Math. round((((9*temp)/5) + 32) * 100.0) / 100.0 + " degrees Fahrenheit");
        }
    }
}