Question

Write a method that counts the occurrences of each digit in a string using the following header: public static int[] count(String s) The method counts how many times a digit appears in the string. The return value is an array of ten elements, each of which holds the count for a digit. For example, after executing int[] counts = count("12203AB3"), counts[0] is 1, counts[1] is 1, counts[2] is 2, and counts[3] is 2. Write a test program that prompts the user to enter a string and displays the number of occurrences of each digit in the string. Here is a sample run: Enter a string: 23231adbc1234 2 Digit 1 occurs 2 times Digit 2 occurs 3 times Digit 3 occurs 3 times Digit 4 occurs 1 time

Answer 1

package Lab_4;

 

import java.util.Scanner;

 

public class CountDigitOccurrence {

 

     public static void main(String[] args) {

         

          Scanner input = new Scanner(System.in);

          System.out.print("Enter a string : ");

          String string = input.next();

          input.close();

         

          int[] counts = count(string);

         

          for (int i = 0; i < counts.length; i++) {

               if (counts[i] > 0) System.out.println("Digit " + i + " occurs " + counts[i] + " times");

          }

 

     }

    

     public static int[] count(String s) {

         

          int [] counts = new int[10];

          char[] individual = s.toCharArray();

          int counter = 0;

         

          for (int i = 0; i < counts.length; i++) {

               for (int j = 0; j < individual.length; j++) {

                     if (Character.isDigit(individual[j]) && i == Character.getNumericValue(individual[j])) {

                          counter++;

                     }

               }

               counts[i] = counter;

               counter = 0;

          }

         

          return counts;

     }

 

}