Crossett Trucking Company claims that the mean weight of its delivery trucks when they are fully...
Crossett Trucking Company claims that the mean weight of its delivery trucks when they are fully loaded is 5,300 pounds and the standard deviation is 170 pounds. Assume that the population follows the normal distribution. Forty trucks are randomly selected and weighed.
Within what limits will 99 percent of the sample means occur? (Round your z-value to 2 decimal places and final answers to 1 decimal place.)
Sample means _______ to _______
Homework Answers
Mean= 5300
Standard deviation= 170
N= 40
Z critical value=|z| = 2.58
Margin of error= z* sd/√N=( 2.58)(170/√40)= 69.1
5300± 69.1
Sample means 5230.9 to 5369.1
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Crossett Trucking
Company claims that the mean weight of its delivery trucks when
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Crossett Trucking Company claims that the mean weight of its delivery trucks when they are fully loaded is 5,950 pounds and the standard deviation is 130 pounds. Assume that the population follows the normal distribution. Forty trucks are randomly selected and weighed. Within what limits will 95 percent of the sample means occur? (Round your z-value to 2 decimal places and final answers to 1 decimal place.)
Crossett Trucking Company claims that the mean weight of its delivery trucks when they are fully...
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Please help ill be sure to rate Crossett Trucking Company claims that the mean weight of...
Please help ill be sure to rate Crossett Trucking Company claims that the mean weight of its delivery trucks when they are fully loaded is 5,300 pounds and the standard deviation is 170 pounds. Assume that the population follows the normal distribution. Forty trucks are randomly selected and weighed. Within what limits will 99% of the sample means occur? (Round your z-value to 2 decimal places and final answers to 1 decimal place.)
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