Question

Given an int variable grade, based on its value, assign a char variable letterGrade in the following way: 90 and above, ‘A’, 80 ~89, ‘B’, etc in java.

Answer 1

import java.util.Scanner;

public class LetterGrade {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        System.out.print("Enter score: ");
        int value = in.nextInt();
        char letterGrade;
        if (value >= 90) {
            letterGrade = 'A';
        } else if (value >= 80) {
            letterGrade = 'B';
        } else if (value >= 70) {
            letterGrade = 'C';
        } else if (value >= 60) {
            letterGrade = 'D';
        } else {
            letterGrade = 'F';
        }
        System.out.println("grade is " + letterGrade);
    }
}