Matlab:
Study the effects of damping by starting a pendulum (use l = 9.81 m and q = 0.1) with an initial displacement (θ = 0.5 rad, for example). Estimate the time constant for the decay of the pendulum oscillation obtained with these values.
% compute the knee angle (térdszög számolása)
v1 = m1(:,2:3)-m2(:,2:3);
v2 = m3(:,2:3)-m2(:,2:3);
% magnitude of both vectors (mindkét vektor hossza)
magv1 = sqrt(v1(:,1).^2 + v1(:,2).^2);
magv2 = sqrt(v2(:,1).^2 + v2(:,2).^2);
% scalar product of v1 and v2 (v1 és v2 skalárszorzata)
v1dotv2 = dot(v1,v2,2);
% computing the angle (szögek számítása)
alpharad = acos(v1dotv2./(magv1.*magv2));
% plot the results (Eredmény kiiratása)
offset = 119; % offset
Tsamp = 1/30; % sampling time - idő mintavétel
t = (0:length(alpharad)-1)'*Tsamp; % time vector
alpha=alpharad*180/pi-offset;
figure(1)
subplot(1,2,1)
plot(m1(:,3),-m1(:,2),'rx', m2(:,3),-m2(:,2),'gx',
m3(:,3),-m3(:,2),'bx')
grid
xlabel('x koordinata [pixel]')
ylabel('y koordinata [pixel]')
subplot(1,2,2)
plot(t, alpha)
grid
xlabel('ido [s]' )
ylabel('térdszög [fok]')
Matlab: Study the effects of damping by starting a pendulum (use l = 9.81 m and...
Question 2 The pendulum shown in Figure 2 consists of a concentrated mass m attached to a rod whose mass is small compared to m. The rod's length is L. The equation of motion for this pendulum is Suppose that L 1 m and g 9.81 m/s2. Use MATLAB to solve this equation using symbolic and numerical techniques for, θ(t) for two cases: , θ(0)-0.5 rad and, θ(0)-0.8 rad. In both cases 0(0) 0. Figure 2- A pendulum [3 marks]...
A 62.5 g pendulum has length 10 cm. The bob is released from a starting angle θ = 0.2. The damping constant is k-0.1 Using Laplace Transform, Find an equation for the position at any time t. [10 marks]
A 62.5 g pendulum has length 10 cm. The bob is released from a starting angle θ = 0.2. The damping constant is k-0.1 Using Laplace Transform, Find an equation for the position at any time t. [10 marks]
9. A mechanical component can be modelled as a pendulum with a torsional damper of coefficient, c, at its oO hinge as shown in Figure Q.9. Stiffness in the system is modelled by a spring of stiffness, k, located at the midpoint of the light bar of length 1. The pendulum is free to rotate about the hinge O and has bob-mass m a) Show that the equation of motion of the system for small angular displacements, 6, is given...
A62.5 g pendulum has length 10 cm. The bob is released from a starting angle 8-0.2. The damping constant is k = 0.1. Using Laplace Transform, Find an equation for the position at any time t. (10 marks] 25. e initial ial BLANK
A62.5 g pendulum has length 10 cm. The bob is released from a starting angle 8-0.2. The damping constant is k = 0.1. Using Laplace Transform, Find an equation for the position at any time t. (10...
using matlab
The damping system has a single degree of freedom as follows: dx2 dx m++ kx = + kx = F(t) dt dt The second ordinary differential equation can be divided to two 1st order differential equation as: dx dx F с k x1 = = x2 ,X'2 X2 -X1 dt dt m m m m N F = 10, m = 5 kg k = 40, and the damping constant = 0.1 The initial conditions are [0 0]...
P4. A clock keeps time using the periodic motion of a simple pendulum. The pendulum consists of a string of length L and a bob of mass m-5.00 kg attached to the end of the string. The pendulum has a period T-1.00 s. The initial angle (0) at 0 is equal to 0.175 rad. The bob is released from rest (i.e. -0) at -0. The angle between the string and the vertical is given by the equation: e-a cos (or...
solve by matlab
The damping system has a single degree of freedom as follows: dx2 dx mo++ kx = F(t) dt dt The second ordinary differential equation can be divided to two 1sorder differential equation as: dx dx F C k xí -X2 -X1 dt dt m m m = x2 ,x'z m N F = 10, m = 5 kg k = 40, and the damping constant = 0.1 The initial conditions are [00] and the time interval is...
do (b) and (c) only.
2. For the simple pendulum shown in Figure 2, the nonlinear equations of motion are given by θ(t) + 믈 sin θ(t) + m 0(t)-0 Pivot point L, length Massless rod , mass Figure 2. A simple pendulum 3. Consider again the pendulum of Figure 2 of problem 2 when g = 9.8 m/s, 1 = 4.9m, k =0.3, and (a) Determine whether the system is stable by finding the characteristic equation obtained from setting...
Problem 4. A pendulum is modeled by a mass that is attached to a t y weightless rigid rod. According to Newton's second law, as the 0-1 pendulum swings back and forth, the sum of the forces that are acting on the mass equals the mass times acceleration MASS ACCELERATION FREE BOOY de DIAGRAM DIAGRAM — RL dt mL 3D — тg sin(0) dt2 ma,-mê where L 1.25 m is the length of the pendulum, g = 9.81 m/s2 is...