Question
​Write a function that takes a list as an argument and returns true if the list is already sorted in increasing order. (You should not sort the list, and make sure that you just iterate over the list once! Only one loop!)
WRITE THE CODE IN PYTHON
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Answer #1

python 3 code

============================================================================================

def checkListSorted(l):
for i in range(1,len(l)):
#print(l[i])
if(l[i-1]>l[i]):
return False
  
return True


print(checkListSorted([2,4,5,12]))
print(checkListSorted([2,4,5,12,11]))
print(checkListSorted([2,1,5,89,12]))


============================================================================================

Output

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