A small car weighing 588.0 N is in uniform circular motion along a vertical circle. At the highest point of the ride, the car experiences a normal force of magnitude 528.0 N. What is the normal force the car experiences at the bottom of the circle?
Solution) Weight , mg = 588 N
Normal force at top , Ntop = 528 N
Normal force at bottom , Nbottom = ?
In vertical circular motion
Nbottom = Ntop + 6mg
Nbottom = 528 + 6(588)
Nbottom = 4056 N
A small car weighing 588.0 N is in uniform circular motion along a vertical circle. At...
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A small block with mass 0.0500 kg slides in a vertical circle of
radius 0.0760 m on the inside of a circular track. There is no
friction between the track and the block. At the bottom of the
block's path, the normal force the track exerts on the block has
magnitude 3.70 N
Part A: What is the magnitude of the normal force that the track
exerts on the block when it is at the top of its path?
HW...