Question

You will be given a list of conditions to test for. Write if-statements that display the result if the condition is true. For example, if the condition was x is negative or over 5000, a possible answer would be:

if( x < 0 || x > 5000 )
      System.out.println("x is negative or > 5000.");

Conditions to test for:

1. x is closer in value to y than z is. Consider that all 3 numbers can be any combination of positive, negative and/or zero.

2. Suppose that answer is a String object. Write the code to display if the value of answer is some affirmative because the answer begins with "Y" or "y" as in one of the following: "Yes", "Yo", "YES", "YO", "YUP", "YEAH", , "yo", , "yEs", "yO", "yUp", etc.

Answer 1

Please find the answer below::

ConditionChecker.java

package classes5;

import java.util.Scanner;

public class ConditionChecker {
   public static void main(String[] args) {
       Scanner sc = new Scanner(System.in);
       int x,y,z;
       System.out.print("Enter value of x :");
       x = sc.nextInt();
       System.out.print("Enter value of y :");
       y = sc.nextInt();
       System.out.print("Enter value of z :");
       z = sc.nextInt();
      
       int diff1 = Math.abs(x-y);
       int diff2 = Math.abs(x-z);
       if(diff1<diff2){
           System.out.println("X is closer to Y");
       }else{
           System.out.println("X is closer to Z");
       }
       sc.close();
   }

}

output:

AffirmativeChecker.java

package classes5;

import java.util.Scanner;

public class AffirmativeChecker {
   public static void main(String[] args) {
       Scanner sc = new Scanner(System.in);
       String ans;
       System.out.print("Enter your response : ");
       ans = sc.nextLine();
       ans = ans.toLowerCase();
       System.out.println("\nResponse : ");
       if(ans.length()>0 && ans.charAt(0)=='y'){
           System.out.println("It's YES");
       }else{
           System.out.println("Ohho!!!! It's denied");
       }
       sc.close();
   }

}