What is the maximum distance you could place an Omega Pressure transmitter Model PX119-030G from the current measuring instrument if you are using 24 AWG wire (25Ω/1000ft) and using a 18 VDC power supply?
Considering 5% maximum voltage drop as standard
5% of 18V = 0.9 V
Also max current used by omega transmitter = 20mA
(from data sheet of Model PX119-030G)
So , Voltage drop =0.9 = I * R = 20mA *R
So , R= 0.9/ 20mA = 45 ohms
So 25 ohms have 1000ft length
So 45 ohm will have length = 45*1000/25= 1800 feet
So maximum distance we can use is 1800 feet!!
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You can find datas from here the Link provided:
https://www.youtube.com/channel/UCKZ_Kb4C9j-B3RSNBMv2s_w
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