13. Chi-square: Which of the following values is significant at the .05 level?
14. Calculate Test Statistics By Hand
|
Athletes’’ weight (lbs) |
|
144 |
|
165 |
|
210 |
|
177 |
|
165 |
|
182 |
|
150 |
|
170 |
|
190 |
|
205 |
Mean:
Median:
Mode:
Standard deviation:
Variance:
Range:
13.
| SNO | Caclulated Value | P value | Significant |
| a. | X2(10)=15.43 | 0.117153491 | NO |
| b. | X2(8)=12.20 | 0.142500974 | NO |
| c. | X2(5)=11.12 | 0.04905197 | Yes |
| d. | X2(2)=4.23 | 0.12063329 | NO |
OPTION C is correct.
14.
The sample size is n=10. The provided sample data along with the
data required to compute the sample mean
and sample
variance
are shown in the
table below:
| X | X2 | |
| 144 | 20736 | |
| 165 | 27225 | |
| 210 | 44100 | |
| 177 | 31329 | |
| 165 | 27225 | |
| 182 | 33124 | |
| 150 | 22500 | |
| 170 | 28900 | |
| 190 | 36100 | |
| 205 | 42025 | |
| Sum = | 1758 | 313264 |

Now, in order to compute the median the data needs to be put into ascending order, as shown in the table below
| Position | X (Asc. Order) |
| 1 | 144 |
| 2 | 150 |
| 3 | 165 |
| 4 | 165 |
| 5 | 170 |
| 6 | 177 |
| 7 | 182 |
| 8 | 190 |
| 9 | 205 |
| 10 | 210 |
Since the sample size n=10 is even, we have that (n+1)/2 = (10+1)/2 = 5.5 is not an integer value, the median is computing by taking the average of the values at the positions 5th and 6th, as shown below

The mode of the data set is 165.
Also, from the information above we get that min=144, max=210, which means that the range is
Range=max−min=210−144=66
Please let me know in comments in case anything is unclear. Will reply ASAP. Do upvote if satisfied!
13. Chi-square: Which of the following values is significant at the .05 level? X2(10)=15.43 X2(8)=12.20 X2(5)=11.12...
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