Question

String data and string manipulations are a major capability in any type of data processing. Character arrays are rather limited compared to String data types.

This application will:

1. Allow the user to enter a string (multiple words including blanks)

2. Determine the number of vowels (a, e, i, o, u) and non vowels.a. Total number of Individual a’s, e’s, i’s, o’s, u’sb. Uppercase vowels count the same as lowercase vowels (i.e. “A” is the same as “a”)c. Any other characters count as “non vowels”

3. Allow the user to run this application as many times as they wish

Output example:

Enter a string of text: Space the final frontier

There are 24 characters in "Space the final frontier"

"Space the final frontier" has:

2 A's

3 E's

2 I's

1 O's

0 U's

16 non vowels

Enter Another string (Y or N):

Answer 1

import java.util.Scanner;

public class CountVowels {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String line, choice;
        char ch;
        while (true) {
            System.out.print("Enter a string of text: ");
            line = in.nextLine();
            System.out.println("There are " + line.length() + " characters in \"" + line + "\"");
            System.out.println("\"" + line + "\" has:");
            int a = 0, e = 0, i = 0, o = 0, u = 0;
            for (int j = 0; j < line.length(); j++) {
                ch = Character.toLowerCase(line.charAt(j));
                if (ch == 'a') a++;
                else if (ch == 'e') e++;
                else if (ch == 'i') i++;
                else if (ch == 'o') o++;
                else if (ch == 'u') u++;
            }
            System.out.println(a + " A's");
            System.out.println(e + " E's");
            System.out.println(i + " I's");
            System.out.println(o + " O's");
            System.out.println(u + " U's");
            System.out.println((line.length() - (a+e+i+o+u)) + " non vowels");
            System.out.print("Enter Another string (Y or N): ");
            choice = in.nextLine();
            if (choice.equalsIgnoreCase("n")) {
                break;
            }
        }
    }

}