Question

A fairgrounds ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has a 8.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose magnitude is 2.45 times that due to gravity?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

a = 2.45*g

= 2.45*9.8 m/s^2

= 24.01 m/s^2

= v^2/r = r*ω^2

so ω = sqrt(a/r) = sqrt(24.01/8.00) = 1.732 rad/s

= 1.732*60/2pi rev/min

= 16.54 rev/min

Kindly rate :)

Add a comment
Know the answer?
Add Answer to:
A fairgrounds ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT