Suppose the heights of women at a college are approximately Normally distributed with a mean of 64 inches and a population standard deviation of 1.5 inches. What height is at the 15th percentile? Include an appropriately labeled sketch of the Normal curve to support your answer.
For 15th percentile z = -1.036
So, 62.45 inches is the height at 15th percentile.
This is the normal curve to support the answer.
Please comment if any doubt. Thank you.
Suppose the heights of women at a college are approximately Normally distributed with a mean of...
Suppose the heights of women at a college are approximately Normally distributed with a mean of 66 inches and a population standard deviation of 1.5 inches. What height is at the 10th percentile? Include an appropriately labeled sketch of the Normal curve to support your answer.
Assuming that the heights of college women are normally distributed with mean 67 inches and standard deviation 2.9 inches, answer the following questions. (Hint: Use the figure below with mean and standard deviation o.) Area Under a Normal Curve 19.5% 34% 3 - 30 -20 - + 95% 20% (a) What percentage of women are taller than 67 inches? (b) What percentage of women are shorter than 67 inches? (c) What percentage of women are between 64.1 inches and 69.9...
Assuming that the heights of college women are normally distributed with mean 62 inches and standard deviation 2.6 inches, answer the following questions. (Hint: Use the figure below with mean and standard deviation o.) Area Under a Normal Curve 34% 34% 13.5% 2.35% (a) What percentage of women are taller than 62 inches? 50 % (b) What percentage of women are shorter than 62 inches? (c) What percentage of women are between 59.4 inches and 64.6 inches? (d) What percentage...
2) The heights of men are normally distributed with a mean of 68.6 in and a standard deviation of 2.8 in. The heights of women are normally distributed with a mean of 63.7 in. and a standard deviation of 2.9 in. a) Find the 90th percentile of the heights of women. b) Which of these two heights is more extreme relative in the population from which it came: A woman 70 inches tall or a man 74 inches tall? Justify...
If the heights of women are normally distributed with a mean of 65.0 inches and a standard deviation of 2.5 inches and the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches, At 71 inches what is the probability for the height of a person of your gender to be within 3 inches of your height (between “your height – 3 inches” and “your height + 3 inches”)?
In a population of 225 women, the heights of the women are normally distributed with a mean of 64.5 inches and a standard deviation of 2.9 inches. If 25 women are selected at a random, find the probability that their mean height will exceed 66 inches. Assume that the sampling is done without replacement and use a finite population correction factor with N=225. Pls. show solution
Suppose that the heights of adult women in the United States are normally distributed with a mean of 64.5 inches and a standard deviation of 2.3 inches. Jennifer is taller than 75 %of the population of U.S. women. How tall (in inches) is Jennifer? Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.
Suppose that the heights of adult women in the United States are normally distributed with a mean of 65 inches and a standard deviation of 2.5 inches. Jennifer is taller than 90% of the population of U.S. women. How tall (in inches) is Jennifer? Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place. inches x 6
Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The U.S. Army requires that the heights of women be between 58 and 80 inches. If 200 women want to enlist in the U.S. Army, how many would you expect to meet the height requirements? About 197 women
Women’s Heights Assume that Women’s heights are normally distributed with mean μ=63.6 in. and standard deviation σ=2.5 in. Use StatKey to answer the following questions. Include a screenshot from StatKey for each question. Find the percent of women with heights between 58.6 and 68.6 inches. Find the percent of women with heights between 60 inches and 65 inches. Find the height of a woman in the 95th percentile, (taller than 95% of other women.) Life Expectancy Part 4 From the...