Choose the correct response for a DISCRETE
probability situation (this is NOT a correction for continuity
situation): P( 12 ≤ X < 26) =
Options:
P(x ≤ 25) − P(x ≤ 12)
P(x ≤ 26) − P(x ≤ 12)
P(x ≤ 26) − P(x ≤ 11)
P(x ≤ 25) − P(x ≤ 11)
solution
given that
P( 12 ≤ X < 26) =P(x ≤ 25) − P(x ≤ 12)
correct option is P(x ≤ 25) − P(x ≤ 12)
Choose the correct response for a DISCRETE probability situation (this is NOT a correction for continuity...
Choose the correct response for a DISCRETE probability situation (this is NOT a correction for continuity situation): P( 11 ≤ X < 23) = Question 7 options: P(x ≤ 22) − P(x ≤ 11) P(x ≤ 22) − P(x ≤ 10) P(x ≤ 23) − P(x ≤ 10) P(x ≤ 23) − P(x ≤ 11)
Perform a continuity correction to rewrite the probability P(x is no more than 5) that involves a discrete random variable (x) as a probability involving a continuous random variable (x').
The given values are discrete. Use the continuity correction and describe the region of the normal distribution that corresponds to the indicated probability. The probability that the number of correct answers is between 29 and 41 inclusive 308 a. The area between 29.5 and 40.5 b. The area between 29 and 41 c. The area between 28.5 and 40.5 d. The area between 28.5 and 41.5
A binomial probablity is given Write the probability in words. Then, use a continuity correction to convert the binomial probability to a normal distribution probability P(43<x<51) Write the probability in words The probability of getting Which of the following is the normal probability statement that corresponds to the binomial probability statement? O A. P(435 <x <50 5) O B. P(50 5<x<51.5) O C. P(42 5<x<51.5) D. P(x> 515 or x <425) OE. P(x 50 5 or x <435) A binomial...
A binomial probability is given. Write the probability in words. Then, use a continuity correction to convert the binomial probability to a normal distribution probability. P(xs 135) Write the probability in words. The probability of getting 135 successes. Which of the following is the normal probability statement that corresponds to the binomial probability statement? O A. Plx> 135.5) O B. P(x < 135.5) OC. P(x > 134.5) OD. P(134.5<x< 135.5) O E. P(x < 134.5)
Use continuity correction to select the options that correspond to the described region: The probability of 15 or less defective items is the area to the ___(left/right) of ___ (14.5/15/15.5)?
The value given below is discrete. Use the continuity correction and describe the region of the normal distribution that corresponds to the indicated probability. Probability of fewer than 6 passengers who do not show up for a flight. A. The area to the right of 5.5 B. The area to the right of 6.5 C. The area between 5.5 and 6.5 D. The area to the left of 6.5 E. The area to the left of 5.5
Abinomial probability is given. Write the probability in words. Then, use a continuity correction to convert the binomial probability to a normal distribution probability P(74<x<80) Write the probability in words. The probability of getting Which of the following is the normal probability statement that corresponds to the binomial probability statement? OA P(74.5<x<79.5) O B. P(x> 80.5 or x <73.5) OC. Plx> 79.5 or x < 74.5) OD. P(73.5<x<805) O E. P(795<x<80.5) Click to select your answer Type here to search...
given. Write the probability in words. Then, use a continuity correction to convert the binomial probability to a normal distribution probability A binomial probability Px<94) Write the probability in words. 94 successes. The probability of getting Which of the following is the normal probability statement that corresponds to the binomal pobability staterment? O A. P(x> 93.5) O B. P(x<93.5) OC. Px<94.5) O D. P(93.5<x <94.5) O E. Px>94.5) Cick to select your answer javascriptdoExercise(6) Type here to search
+ 6 The giren values are discrete. Use the the region of the normal distribution probability. The probability of continuity that at least correction and describe corresponds to the indicated 44 boys 5. for the binomial distribution with the given Vulwes for in and p. stat whether or not it is suitable to use the normal distrib as an approximation n = 20 and p=0.a