Sol::
Given
Height(h) = 2.7 m
The time off the ground is double the time it would take to drop
1.65m., as the time is identical from ground to maximum height, and
from maximum height back to ground.
So
t = √(2h/g)
=√(2*2.7/9.8)
= 0.742 s
Doubling it, we get t=1.484 secs.
So Ans:
T= 1.48 s
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