Question

Problem 3: HorseWeights

In C++ Please

Research shows that horses are satisfied when they consume an amount equivalent to a certain percentage of their body weight on a daily basis. Depending on the horse type, some are satisfied with as little as 1.8% of their body weight, but others may require up to 3.2% of their body weight. An average of 2.0% is a good starting point for most “maintenance” and “light work” equines. The intake level for “moderate work” equines is slightly higher at 2.5%. For “growing” equines, “lactating” equines or equines that are subject to “heavy work” start with a 3.0% intake level. Given a list of horse weights and horse types, you are to make a program that should output the amount of feed that each horse needs. Attached is a list of 100 horse weights and horse types in the following format, with each horse weight and horse type on a single line:

1300 moderate work

700 growing

1232 moderate work

1300 heavy work

1320 lactating

760 growing

…

Read in the data into 2 arrays of appropriate type. Then make a function that will have 2 parameters; a single horse’s body weight, and the horse’s type. The function should return the horse’s amount of feed.

You will then output the index number for each horse, 1-100, and how much feed that equine should receive. (Note that we will use pounds for the body weight, and therefore our amount of feed will also be in pounds.)

Here is an example of some output – using the sample input from above:

Horse # Amount of Feed

1 32.5

2 21

3 30.8

4 39

5 39.6

6 22.8

Answer 1

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# This function takes two inputs i.e. the weight of the horse and the type of the horse

# Then it returns the amount of food that needs to be fed to the horse

def food_needed(weight,type):

    if type== "growing" or type== "lactating" or type== "heavy work":

        return weight*0.03

    elif type =="maintenance" or type=="light work":

        return weight*0.02

    # If none of the above two cases get executed then it means that the horse is doing moderate work and its 2.5 percent of food needed

    else:

        return weight*0.025

# The line variable is for reading every line

line=" "

# This array stores all the weights of the horses

horse_weight=[]

# This array stores the type of the horses

horse_type=[]

while True:

    line=input()

    # The input loop breaks if there is an empty line

    if len(line)==0:

        break

    arr=line.split()

    # The first item when we split the input line is the weight of the horse

    horse_weight.append(int(arr[0]))

    # Then we find the first space and the words after that mention the type of the horse

    index=line.find(" ")

    horse_type.append(line[index+1:])

# For all the inputs in the array we print the amount of food needed

for i in range(len(horse_type)):

    print("{} {}".format(i+1,food_needed(horse_weight[i],horse_type[i])))

If there is any code then refer to the images given for the proper indentation of the code

Hope this helps
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Happy Coding :) :)
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