If the following equation, Cr+3 + HClO4 ----------- Cr2O7-2 + Cl-, is balanced by the ion-electron method in acid solution, a correct term in the balanced equation is
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If the following equation, Cr+3 + HClO4 ----------- Cr2O7-2 + Cl-, is balanced by the ion-electron...
write the balanced equation for the following reaction in acidic solution: Cr2O7 ^2- + C2H6O---> Cr^3+ + C2H4O
Balance the equation in aqueous acidic solution: Cr2O7^2-(aq) + SO3^2-(aq) → SO4^2-(aq) + Cr^3+(aq)
Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): MnO2 (s) + Cl → Mn2+ + Cl2 (g) (b) (acid solution): NaBiO; (s) + Ce3+ BiO+ + Ce4+ + Na+ (c) (basic solution): Fe(OH)2 (s) + CrO42- → Fe,0, (s) + Cr(OH)4
3. Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): Cr0(aq) + U" (aq) → Cr" (aq) +UO; (aq) (b) (acid solution): Cr(s) + O2(g) → Cr* (aq) (C) (basic solution): P. (s) + OH' (aq) → PH; (g) + H2PO2 (aq)
Write a balanced half-reaction for the oxidation of chromium ion Cr+3 to dichromate ion Cr2O−27 in basic aqueous solution.
Question 1 (4 points) Given the following balanced equation Cr, 0,2- + 3 H2O +8 H+ + 2 Cr3+ + 3 0, +7H,O What is the total number of electrons transferred in the balanced reaction? Please enter a number. What is the oxidation number of Cr in the dichromate ion? Please enter a number such as +2 or -2.
(a) Balance the following half-reactions by the ion-electron half-reaction method: (i) (acid solution) Cl– (aq) → ClO3– (aq) (ii) (acid solution) MoO3 (s) → Mo (s) (iii) (base solution) P4 (s) → H2PO2– (aq) (iv) (base solution) Se (s) → SeO32– (aq) (b) Which of the above equations are oxidation half-reactions? (c) Give the formulas of the reactants that become oxidized in the course of the reaction.
Select the chemical equation that is balanced: 2 Cr + 3 HCl → 2 CrCl3 + 3 H2 2 Cr + 6 HCl → 2 CrCl3 + 3 H2 Cr + 3 HCl → CrCl3 + 3 H2
In nacl molecule, the interaction potential between na ion and cl ion fits the following equation: V(r)=-e2/r+ α.e-r/q in this equation, the first term hammer is the coulomb potential,the second term results from the distribution of other electrons in the system. The equilibrium position between the two ions is where the potential is minimum: f(r)=-dV/dr=e2/r2- α/q . e-r/q =0 the root of this equation gives the r0 bond length.experimental for NaCl α=1.09*103 eV,q=0.33 A and e2 =14.4 A eV Write the c...
balance the following equation by the ion electron
method:
Balance the following equation by the ion-electron method: Cr2O3 + H2S --> Crd+ + S O A 14H+ + Cr203- + H2S --> 2Cr3+ + S + 7H20 o B 8H+ + Cr202 + H2S - - > 2Cr3+ + S + 7H20 O C 8H+ + Cr203- + 3H2S - - > 2Cr3+ + 35 + 7H20 O D 14H+ + Cr2O3 + H2S - - > Cr3+ + S...