The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y=mx+by=mx+b.
Order | Integrated Rate Law | Graph | Slope |
0 | [A]=−kt+[A]0[A]=−kt+[A]0 | [A] vs. t[A] vs. t | −k |
1 | ln[A]=−kt+ln[A]0ln[A]=−kt+ln[A]0 | ln[A] vs. tln[A] vs. t | −k |
2 | 1[A]= kt+1[A]01[A]= kt+1[A]0 | 1[A] vs. t1[A] vs. t | k |
Part A
The reactant concentration in a zero-order reaction was 8.00×10^{−2} MM after 130 ss and 4.00×10^{−2} MM after 380 ss . What is the rate constant for this reaction?
Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash.
Part C
The reactant concentration in a first-order reaction was 8.00×10^{−2} MM after 25.0 ss and 4.90×10^{−3} MM after 60.0 ss . What is the rate constant for this reaction?
Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash.
Part D
The reactant concentration in a second-order reaction was 0.460 MM after 300 ss and 3.60×10^{−2} MM after 705 ss . What is the rate constant for this reaction?
Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash.
The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they...
+ Using Integrated Rate Laws The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y = mx + b. Slope Order O 1 2 Integrated Rate Law Graph [A] = - kt + [A] [A] vs. t In[A] = -kt + In[A], In[A] vs. t LÀ=kt + TA LÀ vs. t -k Review Constants Periodic Table Part A The reactant concentration in a zero-order reaction was...
+ Using Integrated Rate Laws The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y = mx + b. Slope Order O 1 2 Integrated Rate Law Graph [A] = - kt + [A] [A] vs. t In[A] = -kt + In[A], In[A] vs. t LÀ=kt + TA LÀ vs. t -k Review Constants Periodic Table Part A The reactant concentration in a zero-order reaction was...
± Using Integrated Rate Laws Part A The reactant concentration in a zero-order reaction The integrated rate laws for zero-, first-, and second order reaction may be arranged such that they resemble the equation for a straight line y=mx + b was 9.00x102 M after 155 s and 3.50x102 M after 320 s. What is the rate constant for this reaction? Express your answer with the appropriate units Indicate the multiplication of units, as necessary explicitly either with a multiplication...
ing Integrated Rate Laws < 10 of 11 > Review Constants Periodic Table ne integrated rate laws for zero, first- and second-order eaction may be arranged such that they resemble the equation or a straight line, ymr + b Part A Order 0 Integrated Rate Law Graph Slope [A] = - kt +(Alo (A) vs. t -k In A-kt+In Al In A vs. t -k Avst k 1 The reactant concentration in a zero order reaction was 8.00-10-2 Mafter 160...
3 of 19 ReviewConelants1 Pariodc Table The integrated rate laws for zero, Srst, and second-order meaction may be arranged such that they resemble the aquation for a straight line, sy me+b Part A Order Integrated Rate Law Graph Slope A t+A In A)-kt+In A In A) vs. t The reactant concentration in a zero-order reaction was 0 100 Maher 140s and 1.50-10 reaction? A vs. -A Malter 355 What is the ate contant for is 1 -k Express your answer...
us Course Home Homework Chapter 14 Using Integrated Rate Laws 8 of 16 > The integrated rate laws for zero-, f and second- order reaction may be arranged such that they resemble the equation for a straight line y = m + b a Review Constants Periodic Table The reactant concentration in a first-order reaction was 9.90x10-2 Mator 35.0 and 240x10-3 Matter 65.0 s What is the rate constant for this reaction? Express your answer with the appropriate units, Indicate...
HW 4 ± Using Integrated Rate Laws Resources previous | 1 of 11 | next» ± Using Integrated Rate Laws Part A The integrated rate laws for zero-, first-, and second- order reaction may be arranged such that they resemble the equation for a straight line y=mx + b Mafter 125 s and 3.00x10 M The reactant concentration in a zero-order reaction was 6.00x10 after 305 s. What is the rate constant for this reaction? Express your answer with the...
Part A The reactant concentration in a zero-order reaction was 6.00×10?2M after 105 s and 4.00×10?2M after 335 s . What is the rate constant for this reaction? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. Part B What was the initial reactant concentration for the reaction described in Part A? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary,...
The reactant concentration in a zero-order reaction was 0.100 M after 165 s and 2.50×10−2M after 345 s, and the rate constant of the reaction is 4.17*10 What was the initial reactant concentration for the reaction described in Part A? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. The integrated rate laws for zero-, first-, and second-order may be arranged such that they resemble the...
Part A The reactant concentration in a zero-order reaction was 7.00×10−2M after 105 s and 1.50×10−2Mafter 345 s . What is the rate constant for this reaction? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. Part B What was the initial reactant concentration for the reaction described in Part A? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly...