| Given this information: |
| Lead-time demand = 620 pounds |
| Standard deviation of lead time demand = 50 pounds (Assume normality.) |
| Acceptable stockout risk during lead time = 4 percent |
| Use Table. |
| a. |
What amount of safety stock is appropriate? (Round your answer to the nearest whole number.) |
| Safety stock | units |
| b. |
When should this item be reordered? (Round your answer to the nearest whole number.) |
| ROP | units |
| c. | What risk of stockout would result from a decision not to have any safety stock? (Omit the "%" sign in your response.) |
| Stockout risk | % |
safety stock = z x SDLT where z for the service level of 96% would be 1.75
= 1.75 x 50 = 87.5 =88 units.
ROP = demand during lead time + safety stock
= 620+88 = 708
0 safety stock means z=0, which corresponds to the probability of stock out equal to 50%
Given this information: Lead-time demand = 620 pounds Standard deviation of lead time demand = 50...
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drives averages 53 units (normally distributed), with a standard
deviation of 5 drives. Management wants a 95%
service level. Refer to the standard normal table for
z-values.
a) What value of Z should be applied?
(1.04/1.28/2.06/1.65)
b) How many drives should be carried as safety stock?
__________ units (round your response to the nearest whole
number).
c) What is the appropriate reorder point? __________ units
(round your response to the...
Demand for walnut fudge ice cream at the Sweet Cream Dairy can
be approximated by a normal distribution with a mean of 21 gallons
per week and a standard deviation of 3.0 gallons per week. The new
manager desires a service level of 90 percent. Lead time is two
days, and the dairy is open seven days a week. (Hint: Work in terms
of weeks.) Use Table B and Table B1. a-1. If an ROP model is used,
what ROP...
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