At t = 0, a particle is located at x = 35 m and has a velocity of 25 m/s in the positive x direction. The acceleration of the particle varies with time as shown in the diagram. What is the velocity of the particle at t = 5.0 s?
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A particle starts from the origin at t = 0 and moves along the positive x axis. A graph of the velocity of the particle as a function of the time is shown in the figure; the v-axis scale is set by vs = 6.0 m/s. (a) what is the coordinate of the particle at t = 5.0 s? (b) what is the velocity of the particle at t = 5.0 s? (c) what is the acceleration of the particle...
The velocity of a particle moving along the x axis is given for t > 0 by vx = (32.0 − 2.00t2) m/s, where t is in s. What is the acceleration of the particle when (after t = 0) it achieves its maximum displacement in the positive x direction?
At t = 0, a particle leaves the origin with a velocity of 9 0 m/s in the positive y direction and moves in the xy plane with a constant acceleration of (2.0i - 4.0j)m/s^2. At the instant the x coordinate of the particle is 15 m, what is the speed of the particle? 10m/S 16 m/s 12 m/s 14 m/s 26 m/s
A particle initially located at the origin has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector v i = 6.00î m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). ( t î + t2 ĵ) m (b) Find the velocity of the particle at any time t. ( î + t ĵ) m/s (c) Find the coordinates of the particle at t = 3.00...
A particle initially located at the origin has an acceleration of vector a = 4.00ĵ m/s2 and an initial velocity of vector v i = 9.00î m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). ( t î + t2 ĵ) m (b) Find the velocity of the particle at any time t. ( î + t ĵ) m/s (c) Find the coordinates of the particle at t = 9.00...
A particle starts from the origin at t = 0 with an initial
velocity of 5.0 m/s along the positive x axis. If the acceleration
is (–3.0i + 4.5j) m/s^2, determine the velocity and position of the
particle at the moment it reaches its maximum x coordinate.
Can someone explain why
when the particle reaches it maximum x coordinate?
At time t = 0, a 4.0 kg particle with velocity v = (5.0 m/s) i - (6.0 m/s) j is at x = 6.0 m, y = 5.0 m. It is pulled by a 2.0 N force in the negative x direction. What is the angular momentum of the particle about the origin? (Express your answer in vector form.) What torque about the origin acts on the particle? (Express your answer in vector form.) At what rate is the...
At time t = 0, a particle has a charge of 11 pc, is located in the z = 0 plane at x = 0, y = 1.9 m, and has a velocity equal to 34 m/s i. Find the magnetic field in the z = 0 plane at the following. (a) x = 1.1 m, y = 2.9 m PT (b) x = 1.9 m, y = 1.9 m DT (c) x = 1.9 m, y = 2.9 m...
A particle initially located at the origin has an initial velocity of vi = 30.0 î m/s + 50.0 ĵ m/s. If the velocity of the particle at t = 5.0 s is v = 12.0 î m/s + 60.0 ĵ m/s, what is the particle's acceleration (in m/s2)? (Express your answer in vector form.)
I'm having problems figuring out the equations for
these questions. a detailed explanation would be great in showing
which equations was used and solving them, thank you much.
At 1-0, a particle is located at x-25 m and has a velocity of 15 m/s in the positive x direction. The acceleration of the particle varies with time as shown in the diagram. What is the velocity of the particle at t 5.0 s? ex (mis) 6.0 50 40 30 20...