Question

You are a botanist looking at variation in flower morphology along the central coast and of...

You are a botanist looking at variation in flower morphology along the central coast and of special interest to you is a species of native sunflower. You think that there's a difference in the number of petals between some populations: population1 and population 2. You believe that population 2 has more petals. You count the number of petals in both populations and get the data.

a.) write a properly worded hypothesis and prediction for this study.

b.) Do the populations have different numbers of petals? Use Rstudio to perform an appropriate statistical test and write a properly formatted results statement.

Data:

Population Petals
Pop 1 1
Pop 1 29
Pop 1 23
Pop 1 30
Pop 1 26
Pop 1 26
Pop 1 5
Pop 1 14
Pop 1 11
Pop 1 3
Pop 1 8
Pop 1 15
Pop 1 14
Pop 1 22
Pop 1 28
Pop 2 39
Pop 2 11
Pop 2 10
Pop 2 30
Pop 2 26
Pop 2 31
Pop 2 19
Pop 2 15
Pop 2 22
Pop 2 33
Pop 2 32
Pop 2 16
Pop 2 32
Pop 2 33
Pop 2 19
0 0
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Answer #1

a)

Null and Alternate Hypothesis

H0: µ2 = µ1(Mean Petals count of Population 2 is same as that of Population 1)

Ha: µ2 > µ1 (Mean Petals count of Population 2 is greater than that of Population 1)

b)

Code:

# Read Data

setwd ("D:/Data")

mydata <- read.csv("Data_23Nov19.csv", header = T)

head(mydata)

pop1 = mydata[mydata$Population=="Pop 1",]

pop2 = mydata[mydata$Population=="Pop 2",]

t.test(pop2$Petals,pop1$Petals, paired = FALSE,alternative = "greater")

Output

 
        Welch Two Sample t-test
 
data:  pop2$Petals and pop1$Petals
t = 2.1594, df = 27.778, p-value = 0.0198
alternative hypothesis: true difference in means is greater than 0
95 percent confidence interval:
 1.59719     Inf
sample estimates:
mean of x mean of y 
 24.53333  17.00000 

Result

Since the p-value is less than 0.05, we reject the null hypothesis in favour of alternate hypothesis.

Conclusion

Mean Petals count of Population 2 is greater than that of Population 1

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