A bobsled makes a run down an ice track starting at 250 m vertical distance up the hill. If there is no friction, what is the velocity at the bottom of the hill?
ANSWER:
given that height h=250 m, g=9.8 m/sec
mgh = 1/2 mv^2
v = √2gh
v = √2(9.81)(250)
v = 70.04 m/sec
A bobsled makes a run down an ice track starting at 250 m vertical distance up...
need help understanding this problem
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