Question

#include <iostream>

#include<string>

#include<vector>

using namespace std;

struct patient

{

string name;

char Gender;

int d,m,y;

string nationality;

int civilID;

int phoneNumber;

string TypeOfInsurance;

};

Activities

I. Declare a variable from the struct Patient called pat.

II. Fill out the information of pat by reading them from the input.

III. Declare a pointer of type Patient called pat_ptr and assign the address of pat to it.

IV. Change the value of name field of pat by accessing it through pat_ptr.

V. Write all the information inside pat on the output by accessing the fields through pat_ptr.

VI. Declare a second variable from the struct Patient called pat2.

VII.

VIII. Declare a vector of type pointer to struct Patient called pat_ptr_vect IX. Add the address of pat and pat2 to this vector.

X. Print the content of pat_ptr_vect on the output with appropriate prompts.

XI. Include the final code and your outputs inside your workbook and reflect on them.

Answer 1

#include <iostream>
#include<string>
#include<vector>
using namespace std;

struct patient
{
string name;
char Gender;
int d,m,y;
string nationality;
int civilID;
int phoneNumber;
string TypeOfInsurance;
};
int main()
{
//Declare a variable from the struct Patient called pat.
struct patient pat;
  
//Fill out the information of pat by reading them from the input.
cout<<"Enter name ---------> ";
cin>>pat.name;
cout<<"Enter Gender ---------> ";
cin>>pat.Gender;
cout<<"Enter DOB as d,m,y ---------> ";
cin>>pat.d>>pat.m>>pat.y;
cout<<"Enter nationality ---------> ";
cin>>pat.nationality;
cout<<"Enter civilID ---------> ";
cin>>pat.civilID;
cout<<"Enter phone Number ---------> ";
cin>>pat.phoneNumber;
cout<<"Enter Insurance type ---------> ";
cin>>pat.TypeOfInsurance;
  
// Declare a pointer of type Patient called pat_ptr and assign the address of pat to it.
struct patient* pat_ptr=&pat;
  
//Change the value of name field of pat by accessing it through pat_ptr
pat_ptr->name="Krishna";
cout<<endl;
  
// Write all the information inside pat on the output by accessing the fields through pat_ptr.
cout<<"The Detailed information is -----> "<<endl;
cout<<"Name ----------> "<<pat_ptr->name<<endl;
cout<<"Gender ----------> "<<pat_ptr->Gender<<endl;
cout<<"Date of birth ----------> "<<pat_ptr->d<<"-"<<pat_ptr->m<<"-"<<pat_ptr->y<<endl;
cout<<"nationality ----------> "<<pat_ptr->nationality<<endl;
cout<<"Civil Id ----------> "<<pat_ptr->civilID<<endl;
cout<<"Phone Number ----------> "<<pat_ptr->phoneNumber<<endl;
cout<<"Insurance Type ----------> "<<pat_ptr->TypeOfInsurance<<endl;
  
//Declare a second variable from the struct Patient called pat2
struct patient pat2;
  
//Declare a vector of type pointer to struct Patient called pat_ptr_vect
vector<struct patient*> pat_ptr_vect;
  
//Add the address of pat and pat2 to this vector.
pat_ptr_vect.push_back(&pat);
pat_ptr_vect.push_back(&pat2);
cout<<endl;
  
//Print the content of pat_ptr_vect on the output with appropriate prompts.
//Only 'pat' have data and 'pat2' is empty So, it shows the information of 'pat' only.
cout<<"The Content of vector is -----> "<<endl;
vector<struct patient*>::iterator it=pat_ptr_vect.begin(); //Pointing to beginning address
cout<<"Name ----------> "<<pat_ptr_vect[0]->name<<endl;
cout<<"Gender ----------> "<<pat_ptr_vect[0]->Gender<<endl;
cout<<"Date of birth ----------> "<<pat_ptr_vect[0]->d<<"-"<<pat_ptr_vect[0]->m<<"-"<<pat_ptr_vect[0]->y<<endl;
cout<<"nationality ----------> "<<pat_ptr_vect[0]->nationality<<endl;
cout<<"Civil Id ----------> "<<pat_ptr_vect[0]->civilID<<endl;
cout<<"Phone Number ----------> "<<pat_ptr_vect[0]->phoneNumber<<endl;
cout<<"Insurance Type ----------> "<<pat_ptr_vect[0]->TypeOfInsurance<<endl;
}