Alkalinity: The approximate alkalinity of a water sample is 2.21 x 10-2 M at pH=10.33. Determine the concentration of carbonate (CO32-) in M and mg/L as CaCO3. (pKa=10.33).
Answer: [CO32-] = 7.37x10-3 M and 737 mg/L as CaCO3
Please show the solution to this problem.
Given,
The alkalinity of a water sample = 2.21 x 10-2 M at pH=10.33.
Alkalinity of water is the ratio between ionic weight of CO32- ions and the molecular mass of CaCO3 .
Alkalinity = (concentration of CO32- x molecular mass of CaCO3 ) / Ionic weight of CO32-
We know,
molecular mass of CaCO3 = 100 g/mol
Ionic weight of CO32- = 60 g/mol
Substituting the values,
2.21 x 10-2 = ( c x 100 ) / 60
c =( 2.21 x 10-2 x 60 ) / 100 = 0.01326 M = 1.326 mg/L
I hope the provided answer may be wrong. I suggest you to recheck it.
Best Wishes.
Alkalinity: The approximate alkalinity of a water sample is 2.21 x 10-2 M at pH=10.33. Determine...
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