How many grams of KClO3KClO3 are needed to form 28.3 g28.3 g of O2O2? 2KClO3(s)⟶2KCl(s)+3O2(g)2KClO3(s)⟶2KCl(s)+3O2(g) Step...

Question

Question

How many grams of KClO3KClO3 are needed to form 28.3 g28.3 g of O2O2?

2KClO3(s)⟶2KCl(s)+3O2(g)2KClO3(s)⟶2KCl(s)+3O2(g)

Step 1: Show the strategy for solving this problem.

step 2: Show the conversions required to solve this problem and calculate the grams of KClO3KClO3.

science chemistry

Answer 1

Answer #1

2KClO3(s)⟶2KCl(s)+3O2(g)

3 moles of O2 produced from 2 moles of KClO3

3*32g of O2 produced from 2*122.5g of KClO3

28.3g of O2 produced from = 2*122.5*28.3/(3*32) = 72.22g of KClO3 >>>>>answer

Answer 2

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