Determine the value of n in the Nernst equation for the following reactions: CH4(g) + 2...

Question

Question

Determine the value of n in the Nernst equation for the following reactions:

CH₄(g) + 2 O₂(g) → CO₂(g) + 2 H₂O(l)

2 NO₃^-(aq) + 4 H⁺(aq) + Cu⁺(aq) → 2 NO₂(g) + 2 H₂O(l) + Cu²⁺(aq)

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Answer 1

Answer #1

(1) CH₄ (g) + 2 O₂ (g) CO₂ (g) + 2 H₂O (l)

Oxidation number of carbon in CH₄ is -4

Oxidation number of carbon in CO₂ is +4

change in oxidation number for carbon = final oxidation number - initial oxidation number

change in oxidation number for carbon = +4 - (-4)

change in oxidation number for carbon = 4 + 4

change in oxidation number for carbon = 8

Value of n is 8

(2) 2 NO₃^- (aq) + 4 H⁺ (aq) + Cu (aq) 2 NO₂ (g) + 2 H₂O (l) + Cu²⁺ (aq)

Oxidation number of copper in Cu is 0

Oxidation number of copper in Cu²⁺ is +2

change in oxidation number for copper = final oxidation number - initial oxidation number

change in oxidation number for copper = +2 - (0)

change in oxidation number for copper = 2

Value of n is 2

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Answer 2

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