Question

A bone mineral density rest is used to identify a bone disease. The result of a bone density test is commonly measured as a z score, and the population of z scores is normally distributed with a mean of 0 and a standard deviation of 1.

For a randomly selected subject, find the probability of a bone density test score greater than -1.54. Round to 4 decimal places.

Answer 1

Let Z be the score of bone mineral density test.

For a randomly selected subject, the probability of a bone density test score greater than -1.54 is given by

P(Z>-1.54)=1-P(Z<-1.54)

=1- 0.6178 ----------------By using z table.

=0.9382

#P(Z>-1.54)=0.9382