A single slit of width 0.65 mm is illuminated with monochromatic light (λ = 630 nm). A screen is placed 2.50 m from the slit to observe the fringe pattern. What is the distance from the main principle axis and the fourth dark fringe?
y = n * lambda * D / d
= (4 * 630 * 10^{-9} * 2.5) / (0.65 * 10^{-3})
= 9.69 * 10^{-3} m
= 0.969 cm
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