Question

A single slit of width 0.65 mm is illuminated with monochromatic light (λ = 630 nm). A screen is placed 2.50 m from the slit to observe the fringe pattern. What is the distance from the main principle axis and the fourth dark fringe?

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Answer #1

y = n * lambda * D / d

= (4 * 630 * 10-9 * 2.5) / (0.65 * 10-3)

= 9.69 * 10-3 m

= 0.969 cm

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