A train of length L accelerates uniformly from rest. If the front of the train passes a railway worker a distance x down the track at a speed of v, what will be the speed vL of the last car as it passes the worker? Express your answer in terms of the given symbols.
Here,
let the acceleration of the train is a
when it travels a distance x , it's velocity becomes v
Using third equation of motion
v^2 - 0^2 = 2 * a * x
a = v^2/(2x)
NOw, for total distance (L + x)
vL^2 - 0^2 = 2 * a * (x + L)
vL^2 = 2 * v^2 * (x + L)/(2x)
vL = v * sqrt((x+L)/x)
the final velocity of the last car is v * sqrt((x+L)/x)
A train of length L accelerates uniformly from rest. If the front of the train passes...
Constants Part A A 75-m-long train begins uniform acceleration from rest. The front of the train has a speed of 18 m/s when it passes a railway worker who is standing 145 m from where the front of the train started (see the figure below). Figure 1) What will be the speed of the last car as it passes the worker Express your answer to two significant figures and include the appropriate units. Value Units Submit uest Ans Provide Feedback...
A 75-m-long train begins uniform acceleration from rest. The front of the train has a speed of 18 m/s when it passes a railway worker who is standing 200 m from where the front of the train started. What will be the speed of the last car as it passes the worker?
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