The equilibrium constant, Kp, for the following
reaction is 10.5 at 350 K.
2CH2Cl2(g)
=CH4(g)
+ CCl4(g)
If ΔH° for this reaction is -18.8 kJ, what is the
value of Kp at 441 K?
Kp =
The equilibrium constant, Kp, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) =CH4(g) + CCl4(g)...
The equilibrium constant, Kp, for the following reaction is 10.5 at 350 K: 2CH2Cl2(g) > CH4(g) + CCl4(g) Calculate the equilibrium partial pressures of all species when CH2Cl2(g) is introduced into an evacuated flask at a pressure of 0.939 atm at 350 K. PCH2Cl2 = atm PCH4 = atm PCCl4 = atm
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g)----> CH4(g) + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.59×10-2 M CH2Cl2, 0.181 M CH4 and 0.181 M CCl4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.134 mol of CCl4(g) is added to the flask? [CH2Cl2] = _____ M [CH4] = _____ M [CCl4] = _____ M
Consider the following reaction where Kp = 10.5 at 350 K. 2CH2Cl2(g) CH4(g) + CCl4(g) If the three gases are mixed in a rigid container at 350 K so that the partial pressure of each gas is initially one atm, what will happen? Indicate True (T) or False (F) for each of the following: 1. A reaction will occur in which CH2Cl2(g) is produced. 2. Kp will increase. 3. A reaction will occur in which CH4 is consumed. 4. Qp...
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) CH4(g) + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.21×10-2 M CH2Cl2, 0.169 M CH4 and 0.169 M CCl4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.139 mol of CCl4(g) is added to the flask? [CH2Cl2] = M [CH4] = M [CCl4] = M
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) CH4(g) + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.39×10-2 M CH2Cl2, 0.175 M CH4 and 0.175 M CCl4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.118 mol of CCl4(g) is added to the flask?
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) CH4(g) + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.49×10-2 M CH2Cl2, 0.178 M CH4 and 0.178 M CCl4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.143 mol of CH4(g) is added to the flask? [CH2Cl2] = M [CH4] = M [CCl4] = M
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) = CH4(g) + CC14(9) Calculate the equilibrium concentrations of reactant and products when 0.377 moles of CH,Cl2 are introduced into a 1.00 L vessel at 350 K (CH2Cl2] = [CH4] = [CCl4] =
The equilibrium constant, Kc, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) = CH4(g) + CCl4(g) Calculate the equilibrium concentrations of reactant and products when 0.294 moles of CH2Cl2 are introduced into a 1.00 L vessel at 350 K. [CH2Cl2] = ? M [CH4] = ? M [CCl4] = ? M
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) CH4(g) + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.09E-2 M CH2Cl2, 0.165 M CH4 and 0.165 M CCl4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.82E-2 mol of CH2Cl2(g) is added to the flask? [CH2Cl2] = M [CH4] = M [CCl4] = M
The equilibrium constant, K, for the following reaction is 10.5 at 350 K. 2CH2Cl2(g) CH4(g) + CCl4(g) An equilibrium mixture of the three gases in a 1.00 L flask at 350 K contains 5.32×10-2 M CH2Cl2, 0.172 M CH4 and 0.172 M CCl4. What will be the concentrations of the three gases once equilibrium has been reestablished, if 2.73×10-2 mol of CH2Cl2(g) is added to the flask?