A 5.71-pF spherical capacitor carries a charge of 1.70 µC.
(a) What is the potential difference across the capacitor?
(b) If the radial separation between the two spherical shells is 6.66 ✕ 10^{−3} m, what are the inner and outer radii of the spherical conductors? Hint: The capacitance of a spherical capacitor is
C = 4πε_{0}[r_{in}r_{out}/(r_{out} − r_{in})].
r_{in} = ________ m
r_{out} = ________ m
When solving b, please explain to me how you were able to get the r_{in} and r_{out} when you completed the problem and started "solving" for it.
A 5.71-pF spherical capacitor carries a charge of 1.70 µC. (a) What is the potential difference...
A spherical capacitor has an inner-shell radius of 4.10 cm and an outer-shell radius of 7.70 cm. (The capacitance of a spherical capacitor is C = 4πε0[rinrout/(rout − rin)].) (a) What is the capacitance of this capacitor? F (b) When connected to a battery, the capacitor carries a charge of 7.10 µC. What is the voltage of the battery? V
The space between two concentric conducting spherical shells of radii b = 1.70 cm and a = 1.20 cm is filled with a substance of dielectric constant κ = 20.5. A potential difference V = 62.0 V is applied across the inner and outer shells. (a) Determine the capacitance of the device. (b) Determine the free charge q on the inner shell. (c) Determine the charge q' induced along the surface of the inner shell.
A spherical capacitor contains a charge of 3.40 nC when connected to a potential difference of 200.0 V. Its plates are separated by vacuum and the inner radius of the outer shell is 5.00 cm. Part A For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of A spherical capacitor. Calculate the capacitance. Express your answer in picofarads. IVO ASO ? C = pF Submit Previous Answers Request Answer X Incorrect; Try Again; 29...
A spherical capacitor contains a charge of 3.50 nC when connected to a potential difference of 250 V. If its plates are separated by vacuum and the inner radius of the outer shell is 4.00 cm. Calculate the capacitance. Calculate the radius of the inner sphere. Calculate the electric field just outside the surface of the inner sphere.
A 400-pF capacitor carries a charge of 2.5*10-8 C. What is the potential difference across the plates of the capacitor?
A spherical capacitor contains a charge of 5.00 nC when connected to a potential difference of 220 V. Its plates are separated by vacuum and the inner radius of the outer shell is 2.10 cm. (a) Calculate the capacitance. (b) Calculate the radius of the inner sphere. (c) Calculate the electric field (magnitude) just outside the surface of the inner sphere. Ans:- 22.7pF, 1.9 cm, 1.24e+05 N/C
Exercise 24.11 - Enhanced - with Solution A spherical capacitor contains a charge of 3.10 nC when connected to a potential difference of 250.0 V. Its plates are separated by vacuum and the inner radius of the outer shell is 4.50 cm. Part A For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of A spherical capacitor. Calculate the capacitance. Express your answer in picofarads. Templates Symbols undo redo adet keyboard shortcuts help pF...
(a) Find the capacitance of the cell membrane. (b) Suppose the potential difference across the cell wall is 92 mV. Find the magnitude of the charge stored on either side of the cell wall. hboard> My courses > Spring Semester 2019 SP2019-PHYS-142-001 Topic 3 HW CH18.2 Capacitance due 1/22 Question 3 Partially correct 0.33 points out of 1.00 The fuids Inside and outside a cell are good conductors separated by the cell wall, which is a dielectric. Thus the cell...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...